（一）船长、船员和其他船上在岗人员因在船上工作产生的工资、其他劳动报酬、船员遣返费用、社会保险费用的给付请求；
Brewster has a clear picture of the typical SpeedPro franchisee: midcareer, corporate and ready for a change. They are around 45 to 55 years old, and they have worked for a corporation and hit middle management. “What they do is they step back and say, ‘I’m gonna bet on myself,’” Brewster says.
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Often people write these metrics as \(ds^2 = \sum_{i,j} g_{ij}\,dx^i\,dx^j\), where each \(dx^i\) is a covector (1-form), i.e. an element of the dual space \(T_p^*M\). For finite dimensional vectorspaces there is a canonical isomorphism between them and their dual: given the coordinate basis \(\bigl\{\frac{\partial}{\partial x^1},\dots,\frac{\partial}{\partial x^n}\bigr\}\) of \(T_pM\), there is a unique dual basis \(\{dx^1,\dots,dx^n\}\) of \(T_p^*M\) defined by \[dx^i\!\left(\frac{\partial}{\partial x^j}\right) = \delta^i{}_j.\] This extends to isomorphisms \(T_pM \to T_p^*M\). Under this identification, the bilinear form \(g_p\) on \(T_pM \times T_pM\) is represented by the symmetric tensor \(\sum_{i,j} g_{ij}\,dx^i \otimes dx^j\) acting on pairs of tangent vectors via \[\left(\sum_{i,j} g_{ij}\,dx^i\otimes dx^j\right)\!\!\left(\frac{\partial}{\partial x^k},\frac{\partial}{\partial x^l}\right) = g_{kl},\] which recovers exactly the inner products \(g_p\!\left(\frac{\partial}{\partial x^k},\frac{\partial}{\partial x^l}\right)\) from before. So both descriptions carry identical information;
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The strikes were conducted by the US and Israel as part of Operation Epic Fury.，这一点在谷歌浏览器【最新下载地址】中也有详细论述
Медведев вышел в финал турнира в Дубае17:59